Calculate the efficiency of of aerobic respiration if a cell generates 32 ATP per molecule of glucose?
Mar.03, 2010 in
Aerobic Respiration
Calculate the efficiency of of aerobic respiration if a cell generates 32 atp per molecule of glucose?
Calculate the efficiency of of aerobic respiration if a cell generates 32 atp per molecule of glucose?
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March 3rd, 2010 at 11:48 pm
Do your own homework or you won’t learn anything.
March 3rd, 2010 at 11:53 pm
I’m stuck with stuff like that too…
here’s my q: http://answers.yahoo.com/question/index;_ylt=AiZVN7lAEKuuDZYzPV6TlDvsy6IX;_ylv=3?qid=20081112200119AAYgqMU
anyway, it’s seems slightly less efficient. my book says the usually make 36
March 4th, 2010 at 12:02 am
The efficiency of respiration is 7.3 kcal per mole of ATP times 32 moles of ATP per mole of glucose divided by 686 kcal per mole of glucose, which equals 0.34.
So, about 34% of the potential chemical energy in glucose has been transferred to ATP. The actual percentage is probably higher because ΔG is lower under cellular conditions. The rest of the stored energy is lost as heat.